摘要：Because it is higher thanthe end of the seventh order, it is its firstrejuvenation FGS1=11^2 order, itsny=1, which is equal to the

The highest full -type division of the even number is the division calculation of the 5th order

Under the action of no back -high FGSX step ,

We have already calculated that the highest full -type full value is relatively minimal, which is 2.057

5 -order full -type division value calculation

The highest full -type division is 5 -order division, its ny=1

Its final order is 7th order , its ny=2

Its ending section , up to the number of rejuvenation FGSX steps is:

The known data is substituted into the highest full -type division .

have:

2*1/（√2）= 1.4144

1 4144

It has a maximum of one , and the rejuvenation FGSX steps are reduced .

Because it is higher than the end of the seventh order , it is its first rejuvenation FGS1=11^2 order , its ny=1 , which is equal to the N Y value of the 5th order . The second rejuvenation FGS2 =13^2 order , its ny=2 is 2 times that of the N Y value of the 5th order .

It is obtrusive that the rejuvenation FGS1=11^2 order , or it can only become a rejuvenating high -definition FGS1 cutting point G1 at the 5th order ; Factor: 10/11

if,

He produced a rejuvenation FGS1 cutting point G1 , from his division value: 2.057 , its order ny=1

The number of minimum dividend values ​is obtained, which is its ny value: ny=1

2.057-1=1.057=1 ( takes for integer value )

It is obtained that in the case of cutting , the maximum full -type division of the even number is the division of the 5th order . It has a minimum of one [conjecture] solution .

If he produces a cut -out high -definition FGS1=11^2 -to -order reduction ,

Its reduction rate is:

fgsx tired = (11-1)/11=10/11

Catten to its division value ,

2.057*10/11=1.87=1(take the set value)

After the FGSX shrinkage , it has at least one [conjecture] solution .

It can be calculated that the highest full -type division of the even number is the division of the 5th level. They have at least one [conjecture] solution.

The highest full -type division of the even number, the three n - =1 level below the 11th order : the division of the 1 order, the 3rd order, and the 5th order, all of which are calculated. Values ​​are ≥1 .

They all have at least one [conjecture] number of solutions. ,,

Because it has a full -type division, it must have the highest full -type division . Since, the sections of 3 ny=1 with less than 11th order ( 1 order, level 3 , level 3 , and level 5 ) , their maximum full -type division values ​​are ≥1. They all have at least one [conjecture] number of solutions.

Then based on the calculation above, and

" " Next ", Chapter 5, Conclusion 11,

"After any of the maximum full -scale division values, they have at least the number of ≥1 [conjecture] solution after the order of ≥11."

"Next", 5 Chapter , Conclusion 12,

Any order with a series of all -type, their maximum full -type points are: ≥1 groups, they contain the minimum number of [conjecture] solution, all: ≥1, all of which have at least one group [guess]. untie.

Well.

Thank you for reading!

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See you next week!

来源：芬芬讲科学