def find_last_subsequence(target, source): m = len(target) n = len(source) if m == 0: return 0 if n == 0: return -1 # 逆向匹配，找到最后一个子序列的起始位置 i = m - 1 j = n - 1 while i >= 0 and j >= 0: if target[i] == source[j]: i -= 1 j -= 1 if i == -1: return j + 1 else: return -1# 读取输入target = input.stripsource = input.strip# 调用函数并输出结果result = find_last_subsequence(target, source)print(result)摘要：def find_last_subsequence(target, source): m = len(target) n = len(source) if m == 0: return 0 if n == 0: return -1 # 逆向匹配，找到最后一个子
来源：搞笑与科技